Direction Cosines and Direction ratios ( Practice Questions)

Namita Tiwari 3-D Geometry

Hello readers
It does not matter how slowly you go as long as you do not stop.With this thought, let’s continue our discussion on direction Cosines and ratios. I hope you have already gone through the mentioned topic in detail, if not then first refer the following;

http://namitatiwari.org/2020/04/13/direction-cosines-and-direction-ratios/

As much you do practicals, your understanding will improve.
So take your time and solve the following questions

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37 thoughts on “Direction Cosines and Direction ratios ( Practice Questions)”

  2. Solution
    1.L=1/4,m=0,n=3/4
    2.1/3=1/3,2/3=2/3,2/3=2/3 so PQ and RS is a parallel line
    3.L=1/√17,m=0,n=4/√17 and k=1/√17
    4. angle=cos^-1 √2/3
    5.angle=cos-1 90
    6.48/169-48/169=0 so it is perpendicular line
    6/7=85% done…
    Plz check the ans

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  4. Good morning mam,plz check the answer****1- 0,1/2,√3/2
    3- L=1√17,M=0,n=4/√17
    4- cos invers 1/3
    5- angle= cos 90
    6-. 12/13×4/13+(-3/13)×12/13+(-4/13)×3/13=0
    Then 48-48/169=0 it is perpendicular line
    Mam snd the solution question no 2&7

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  11. 1)l=0,m=1/2,n=√3/2
    2)(2,4,4)&(2,4,4)both are same therefore they are parallel
    3)a=1,b=0,c=4
    4)cos^-1(√2/√3)
    5)angle=90
    6)48/169-48/169=0 hence angle Will be 90
    7)first line=–1/√6, 1/√6, 2/√6
    Second line=1/√14, 2/√14, 3/√14

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  12. 1)l=0,m=1/2,n=√3/2
    2)(2,4,4)&(2,4,4)both are same therefore they are parallel
    3)a=1,b=0,c=4
    4)cos^-1(√2/√3)
    5)angle=90
    6)48/169-48/169=0 hence angle Will be 90
    7)first line=–1/√6, 1/√6, 2/√6
    Second line=1/√14, 2/√14, 3/√14

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